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NARA [144]
2 years ago
8

A bowling alley has a fixed base cost and charges a variable per game rate. It costs $20.50 for five games and 28.50 for nine ga

mes? What is the variable cost? (Show work
Mathematics
1 answer:
lbvjy [14]2 years ago
8 0


As ordered pairs ( g , C ) where g is the number of games and C is the cost

( 5, 20.50) and ( 9, 28.50)

the slope M = ( 28.50 - 20.50 ) / (9-5)

= 8/4

= 2

So the slope M=$2 per game

Using (5, 20.50)
The intercept B = y - m* g
= 20.50 - 2 * 5
= 20.50 - 10
= 10.50

So the fixed base cost, or FLAT RATE is $10.50.
That is if they played ZER0 games, they still have
to pay $10.50 just to get in.

The linear function is C (g) = 2*g + 10.50

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A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
Select all the distribution shaped for which the mean and median must be about the same.
irga5000 [103]

The distribution shaped for which the mean and median must be about the same will be:

D. Symmetric

E. uniform

<h3>How to illustrate the information?</h3>

In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.

In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.

Therefore, the correct options are D and E.

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

3 0
1 year ago
What is the linear equation 1-3y=4
TEA [102]

1-3y = 4

3у=1-4

3у=-3

У=-1.


6 0
3 years ago
Solve - y = 34. Then graph the solution.
inysia [295]

divide both sides by a negative one to get ride of the -y then on your graph it be a horizontal line at the point (0,-34)

8 0
3 years ago
If the radius of the circle below is 12 feet, find the area of the shaded region.
aniked [119]

Answer:

465.61 ft

Step-by-step explanation:

6 0
3 years ago
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