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denis23 [38]
3 years ago
8

Convert 5,000 inches to feet

Mathematics
2 answers:
borishaifa [10]3 years ago
3 0

There are 12 inches in one foot:

1 ft = 12 in

We want to find how many feet are in 5000 inches:

x ft = 5000 in

Set up a proportion:

1/12 = x/5000

Cross multiply:

12x = 5000

Divide by 12:

x is about 416.67 feet.

balu736 [363]3 years ago
3 0

If 1f = 12in:

5000in / 12 = xf

x = 417.7 approximately.

5000in = 417.7f

Hope it helped,

Happy homework/ study/ exam!

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gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
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You need to borrow $15,000 to buy a car, and you determine that you can afford monthly payments of $325. The bank offers three c
Klio2033 [76]

Answer:

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Step-by-step explanation:

$15k × 8% = $1200 interest

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$16500 ÷ 60months (5years) = $270/mth pymt

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A graphic designer wants to translate rectangle DEFG using T–1, 2(x, y). The pre-image has coordinates D(–1, 3),
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Answer:

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  F +(-1, 2) = (4-1, 1+2) = F'(3, 3)

  G +(-1, 2) = (-1-1, 1+2) = G'(-2, 3)

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A family has $35 to spend on dinner. They spend $18 on entrees. Side dishes are $3 each. What is the greatest number of side dis
natta225 [31]
35-18=17 
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