All categories

3 years ago

Please help me due tomorrow

Mathematics

1 answer:

jekas [21]3 years ago

8 0

3) 0.825

4) 0.1212

5) 0.5455

6) -7.177

7a) 0.066

b) 0.166

c) 0.333

d) 0.416

8) -2/5

9) -7 (32/100) = -7 (9/25)

10) 0.22222 = 2/9

You might be interested in

As she climbs a hill, a cyclist slows down from 25 km/hr to 3 km/hr in 10 seconds. What is her deceleration?

qaws [65]

Deceleration is always the opposite of Acceleration so is negative. So deceleration =-2.2m/s^2

5 0

2 years ago

g The average midterm score of students in a certain course is 70 points. From the past experience it is known that the midterm

spayn [35]

Answer:

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The average midterm score of students in a certain course is 70 points.

This means that $\mu = 70$

29 students are randomly selected and the standard deviation of their scores is found to be 13.15 points.

This means that $\sigma = 13.15, n = 29, s = \frac{13.15}{\sqrt{29}} = 2.44$

Find the probability that the average midterm score of these students is at most 75 points.

This is the pvalue of Z when X = 75. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{75 - 70}{2.44}$

$Z = 2.05$

$Z = 2.05$ has a pvalue of 0.98.

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

8 0

3 years ago

PLEASE HELP ASSAAAPPP (:

Likurg_2 [28]

In the equation $y=a(b)^x$ , a is the initial amount and b is the growth factor. So our initial amount is 30 and our growth factor is 8.3. Your correct choice for this is A.

4 0

3 years ago

Total cost for cookie and lemonade is 1.80. If lemonade costs 1.00 more than the cookie, how much was the lemonade?

Ray Of Light [21]

Answer:

The lemonade costs 1.4.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a cookie.

y is the cost of a lemonade.

Total cost for cookie and lemonade is 1.80.