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uranmaximum [27]
3 years ago
11

PETS Each month Travis spends $20 for premium food$10 for treats $18 for grooming, and $3 for toys for his pet. Write an express

ion that could be used to determine the amount he spends on these items for his pet over a period of 12 months.
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

$492 per year

Step-by-step explanation:

The first step we take towards solving this question is to add all the numbers we were given as money spent(excluding that of the month)

$20 + $10 + $18 + $3 = $41 per month

This means that a total of $41 was spent per month.

Going further, since we're told it's 12 months, we then multiply it by 12, and thus, we have

$41 * 12 = $492 per year

Therefore, the total money spent is $492 per 12 months, or per year

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in parallelogram ABCD, AC is diagonal, the measure <ABC is 40°, and the measure of <ACD IS 57°. what is the measure of &lt
Nutka1998 [239]

Answer: \angle CAD = 83^\circ Option D


Step-by-step explanation:

In this question we use properties of parallelogram and angle sum property of a triangle.

In parallelogram ABCD


\angle ABC=40^\circ


As, we know that opposite angles of parallelogram are equal


Therefore,


\angle ABC =\angle ADC =40^\circ


Now, in triangle ADC

We know that sum of all the angles of a triangle is =180^\circ


\angle ACD +\angle ADC +\angle DAC =180^\circ


57^\circ +40^\circ +\angle DAC =180^\circ


97^\circ + \angle DAC = 180^\circ

Subtracting 97 from both sides we get


\angle DAC = 180^\circ - 97^\circ


\angle DAC = 83^\circ


Measure of \angle CAD = 83^\circ


3 0
3 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
What is √18x^6 written in simplest for? assume all variables are positive.
Nadya [2.5K]

Your answer should be C. 3x^3√2

3 0
3 years ago
⚠️⚠️ Help I’m in desperate need of help ⚠️⚠️ the questions are basically in the top picture
Tom [10]

Answer:

1. 3^{3} * 3^{2}

2.6^{-4}

3. 5^{0} < 5^{1}

7 0
3 years ago
There are a few ways to increase the rate of a reaction. When the amount of a substance in a given volume is increased, this is
RUDIKE [14]
Both of these variables represent a common measure used in chemistry.

The amount of material/volume is the material’s concentration.

The rate is the reaction is increase by altering the concentration.
4 0
3 years ago
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