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Lynna [10]
4 years ago
13

Use the vertical line to determine if the graph is a function or not a function

Mathematics
1 answer:
Alchen [17]4 years ago
8 0

Answer:

It is NOT a function because when putting a vertical line at a point of a graph it crosses 2 points.

Step-by-step explanation:

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Help me solve:<br> 3.14•8^2•23<br> And round to nearest tenth if necessary
Salsk061 [2.6K]

Answer:

4622.1

Step-by-step explanation:

We can use PEMDAS for this

in PEMDAS exponents comes 2nd and in the expression we have exponents so lets solve that first

8^2=64

next is multiplication

so

64*3.14=200.96

200.96*23=4622.08

to round to the nearest tenth we need to look right of the tenths place

since there is an "8" we can round up to "1"

4622.1

Hope this helps

7 0
3 years ago
This homework hella hard i-
nikitadnepr [17]

Answer:

A. 10.00, so total price is currently 40.00

B. 42.8

C. Total amount is 51.36

Step-by-step explanation:

20% of 50 is 10. Taking off 10% (your discount) would make it 40.

7% of 40 is 2.8. The total amount is now 42.8

20% (your tip) of 42.8 = 8.56.

42.8 + 8.56 = 51.36.

51.36 is your final cost.

3 0
3 years ago
Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800. A researcher from the a
Doss [256]

Using the z-distribution, it is found that she should take a sample of 46 students.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:

6\sigma = 800 - 200

6\sigma = 600

\sigma = 100

The sample size is n when M = 29, hence:

M = z\frac{\sigma}{\sqrt{n}}

29 = 1.96\frac{100}{\sqrt{n}}

29\sqrt{n} = 196

\sqrt{n} = \frac{196}{29}

(\sqrt{n})^2 = \left(\frac{196}{29}\right)^2

n = 45.67.

Rounding up, a sample of 46 students should be taken.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
Help help help!!! I don't know how to do it!!!
s344n2d4d5 [400]

Answer:

1,3

Step-by-step explanation: i belive so

5 0
3 years ago
Read 2 more answers
What is the measure of ∠DEG? A) 133° B) 103° C) 77° D) 67°
Lesechka [4]
77° is the answer to your question
7 0
3 years ago
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