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3 years ago

How do you write 304,001 in two forms

Mathematics

1 answer:

a_sh-v [17]3 years ago

6 0

3,000+4,000+1
Three hundred four thousand, one

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Karen and her friends went to dinner at Olive Garden. Their bill was $58 including tax.

tester [92]

Answer:

$69.60

Step-by-step explanation:

58 increase 20% =

58 × (1 + 20%) = 58 × (1 + 0.2) = 69.6

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3 years ago

Solve for X. Round to the nearest tenth of a degree, if necessary.

DerKrebs [107]

The answer is x=52.6

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3 years ago

Can someone help me with this

Helen [10]

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4 years ago

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg

Harman [31]

Answer:

$x=\frac{-5(+/-)\sqrt{5}} {2}$

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=x^{2} +5x+5$

equate the function to zero

$x^{2} +5x+5=0$

$a=1\\b=5\\c=5$

substitute in the formula

$x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}$

$x=\frac{-5(+/-)\sqrt{5}} {2}$

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

6 0

3 years ago

Read 2 more answers

Find a formula for the product P of the solutions of the quadratic equation ax²+bx+c=0 .

Ede4ka [16]

Answer:

product of the roots= c/a

Step-by-step explanation:

The the two roots(α and β) of the quadratic equation ax²+bx+c=0 as given by shridharacharya formula are

$\alpha= \frac{-b+\sqrt{b^2-4ac} }{2a}$

$\beta= \frac{-b-\sqrt{b^2-4ac} }{2a}$

now product of the roots

αβ= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ × $\frac{-b-\sqrt{b^2-4ac} }{2a}$

use formula (a+b)(a-b)= a^2-b^2 and solve we get

αβ= c/a

therefore product of the roots= c/a

8 0

4 years ago