The first thing we must do for this case is to rewrite the function correctly:
"y equals 30 plus 10 sine left bracket startfraction pi over 26 endfraction left parenthesis x minus 14 right parenthesis right bracket"
Rewriting:
y = 30 + 10 * sine [pi / 26 * (x-14)]
We substitute the value of y for each case and clear x.
We have then:
a. 40 comma 000:
40 = 30 + 10 * sine [pi / 26 * (x-14)]
x = 27
b. 35 comma 000
35 = 30 + 10 * sine [pi / 26 * (x-14)]
x = 18.33
c. 25 comma 000
25 = 30 + 10 * sine [pi / 26 * (x-14)]
x = 9.66
Answer:
1/6 ton of fish is fed during the feeding at night.
Step-by-step explanation:
The fish fed in the morning is 
tons, and during after noon the fish fed is 
more than in the morning; or
and let us call the tons of fish fed at night 
, then if the total tons of wish fed during the is 
, we have
Let us add the numerators on the left side and we get:
and subtract 
from both side to isolate 
and since 
, we have
the common denominator of the fractions is 6; therefore, we rewrite the equation as
and subtract the numerators to get:
which the number of tons fed during the feeding at night.
Answer:
36 hours.
Step-by-step explanation:
Answer:
g(19) = 11
Step-by-step explanation:
g(x) = x-8
Let x=19
g(19) = 19-8
g(19) = 11
