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RideAnS [48]
3 years ago
11

Find the average rate of change of f(x)=2x^2-7x from x=2 to x=6

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

Step-by-step explanation:

The average rate of change of a function f between a and b (a< b) is :

R =[f(b)-f(a)] ÷ (a-b)

●●●●●●●●●●●●●●●●●●●●●●●●

Let R be the average rate of change of this function

f(6) = 2×6^2 - 7×6 = 72-42 = 30

f(2) = 2×2^2 - 7×2 = 8-14 = -6

R = [f(6) - f(2)]÷ (6-2)

R = [30-(-6)] ÷ 4

R = -36/4

R = -9

■■■■■■■■■■■■■■■■■■■■■■■■■

The average rate of change of this function is -9

artcher [175]3 years ago
4 0

Answer:

\frac{\Delta y}{\Delta x} =9

Step-by-step explanation:

You can find the average rate of change of any function using the following formula:

Average\hspace{3} rate\hspace{3} of \hspace{3} change=\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1}

Now, let:

x_1=2\\\\and\\\\x_2=6

Let's evaluate the function for x_1 and x_2 :

f(x_1)=2(2)^{2} -7(2)=2*4-7*2=8-14=-6\\\\f(x_2)=2(6)^{2} -7(6)=2*36-7*6=72-42=30

Therefore, the average rate of change of the function over the interval given is:

\frac{\Delta y}{\Delta x} =\frac{f(6)-f(2)}{6-2} =\frac{30-(-6)}{6-2} =9

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Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

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In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

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Therefore, the length of the road is approximately 1677.05 m.

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