Answer:
Step-by-step explanation:
I'm sorry that I cannot show you my work as the equation generator does not support dividing polynomials.
Find rates of change until you find a constant.
dy/dx=1,2,3,4,5,6
d2y/dx2=1,1,1,1,1
So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:
9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...
5a+b=2 and 3a+b=1 and getting this difference...
2a=1, so a=1/2 making 5a+b=2 become:
2.5+b=2, so b=-1/2, making a+b+c=1 become:
1/2-1/2+c=1, so c=1 so the rule is:
a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals
a(n)=(x^2-x+2)/2
Answer:
Step-by-step explanation:
The formula you will want to use for this is one that allows a certain number of compoundings of the interest per year. This is a specific one for compounding continuously, and there is one for finding simple interest. Here is the one we want:
where A(t) is the amount in the account after the compounding occurs over the number of years specified, P is the initial amount in the account, r is the interest rate in decimal form, n is the number of times per year the compounding occurs, and t is the amount of time the money is in the account in years. For us:
P = 300,
r = .04,
n = 4 (quarterly means 4 times), and
t = 10
Filling in:
and
and
and
A(t) = 300(1.488863734) so
A(t) = $446.66 or $447
Answer:
no numbers are missing
Step-by-step explanation:
Don't fool others
