I think it’s x=20 because you multiply both sides of the equation by two and then reduce the numbers with the greatest common factor of 2 and then multiply the numbers
![\huge{\boxed{\frac{12}{14}}} \huge{\boxed{\frac{18}{21}}} \huge{\boxed{\frac{24}{28}}} \huge{\boxed{\frac{30}{35}}} \huge{\boxed{\frac{36}{42}}}](https://tex.z-dn.net/?f=%5Chuge%7B%5Cboxed%7B%5Cfrac%7B12%7D%7B14%7D%7D%7D%20%5Chuge%7B%5Cboxed%7B%5Cfrac%7B18%7D%7B21%7D%7D%7D%20%5Chuge%7B%5Cboxed%7B%5Cfrac%7B24%7D%7B28%7D%7D%7D%20%5Chuge%7B%5Cboxed%7B%5Cfrac%7B30%7D%7B35%7D%7D%7D%20%5Chuge%7B%5Cboxed%7B%5Cfrac%7B36%7D%7B42%7D%7D%7D)
One really simple way to find an equivalent fraction is just to multiply the numerator and denominator.
For example, for the first answer,
, I simply multiplied the numerator and denominator each by 2. This gives you an equivalent fraction.
You can then continue with this process using numbers such as 3, 4, 5, and 6 as your multiplication factor.
ANSWER
0.0952
EXPLANATION
We have that Stephen surveyed 21 of his classmates and obtained the data in the table given.
To find the probability for which a randomly selected classmate has 3 credit cards in their wallet, we have to divide the number of people that had 3 credit cards in their wallet by the total number of people surveyed.
From the frequency table, we have that only 2 classmates had 3 credit cards in their wallets.
Therefore:
![P\left(3creditcards\right)\text{ = }\frac{2}{21}\text{ = 0.0952}](https://tex.z-dn.net/?f=P%5Cleft%283creditcards%5Cright%29%5Ctext%7B%20%3D%20%7D%5Cfrac%7B2%7D%7B21%7D%5Ctext%7B%20%3D%200.0952%7D)
That is the answer.
The answer is d!!! Hope that helps!!