Answer:
y-intercept: (0,5); x-intercept: (5/2, 0)
Step-by-step explanation:
The equation of the line is given: -4x + 7 = 2y - 3.
To find the x-intercept, set y = 0 and solve for x:
-4x + 7 = 0 - 3. This becomes -4x = -10, or x = 5/2. The x-intercept is (5/2, 0).
To find the y-inercept, set x = 0 and solve for y:
0 + 7 = 2y - 3, or 2y = 10, or y = 5. Then the y-intercept is (0, 5).
I think the answer is 19.5
Answer:
A. 2 to the power of 1 over 6
Step-by-step explanation:
![\frac{ \sqrt{2} }{ \sqrt[3]{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B2%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B2%7D%20%7D%20)
Laws of indices subtract ½ from ⅓ and use it as your power
Dm me for more explanation
When solving for this problem, replace x with the first coordinate and solve. if the answer is what you have for the second, it is correct. The first number in an ordered pair is your x and the second is your y. So I would rewrite the equation like this and solve.
y=7x-19 y=7x+21
2=7(3)-19 9=7(4)-19 2=7(3)+21 9=7(4)+21
2=21-19 9=28-19 2=21+21 9=28+21
2=2 9=9 2=42 9=49
as you can see it is the first equation.
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
