PLEASE HELP ME! Find the cube roots of 125(cos 288° + i sin 288°).
1 answer:
◆ COMPLEX NUMBERS ◆
125 ( cos 288 + i sin 288 ) can be written as -
125.e^i( 288)
125.e^i( 288 +360 )
125.e^i( 288+ 720)
[ As , multiples of 360 can be added to an angle without changing any trigonometric functions or sign ]
To find the cube root , take the cube root of above 3 expressions ,
We get -
5 e^( i 96 )
5 e^( i 216 )
5 e^( i 336 )
Now using Euler's formula , We rewrite above as -
5 ( cos 96 + i sin 96 )
5(c os 216 + i sin 216 )
5 ( cos 336 + i sin 336 ) Ans.
You might be interested in
Answer:
(4-m-1)-5
Remove the bracket
= 4-m-1-5
= -2-m
Hope this helps.
Answer:
8x - 20
Step-by-step explanation:
6(2x - 3) - 2(2x + 1)
Distribute
6(2x) -6( 3) - 2(2x) -2( 1)
12x -18 -4x -2
Combine like terms
12x -4x -18 -2
8x-20
Answer:
The reasonings I provided are just examples (they are true, though!). Hope this helps!
Answer:
$39
Step-by-step explanation:
(hope you get a 100%:))
Answer:
14
Step-by-step explanation:
f(2)+g(2)
(2+4)+(2×2+4)
6+8
14