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4 years ago

1. Between which two whole numbers does V5 lie on the number line?

Mathematics

2 answers:

Marysya12 [62]3 years ago

8 0

Answer:

Step-by-step explanation:

We can rewrite 2 as √4 and 3 as √9, and since 4 < 5 < 9, the answer is option B.

podryga [215]3 years ago

4 0

Answer:

I'm pretty sure it's B to

Step-by-step explanation:

Though I think Snog explained it better

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Write the first six cube if natural number

valkas [14]

Answer:

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Step-by-step explanation:

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3 years ago

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I need help please!

Sophie [7]

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

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3 years ago

Find the midpoint of the line segment joining the points R(-5,3) and S(1.6)

Naddik [55]

Answer:

(-2, 4.5)

Step-by-step explanation:

The midpoint formula is $(\frac{x_{1} +x_{2}}{2} ,\frac{y_{1} +y_{2}}{2})$

(-5+1/2, 3+6/2)

(-4/2, 9/2)

Your answer will be (-2, 4.5)

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4 years ago

Denis is looking to buy a new car. He can take a loan out for $10,500 with an interest rate of 5% for 4 years. How much would hi

pochemuha

Answer: 12,600

Step-by-step explanation: 5% of 10,500 is 525. Multiply that by 4 and get 2,100. Add that to 10,500 and you get 12,600.

7 0

3 years ago

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Cabrina and Dabney are attending a conference. After the conference, Cabrina drives home to Boise at an average speed of 7575 m

kifflom [539]

Answer:

Cabrina's time = 5 hours

Dabney's time = 6.5 hours

Step-by-step explanation:

The data of the exercise are:

Cabrina speed = 75 mph

Daney speed = 60 mph

The sum of their distance is 765 miles, therefore

Cabrina's distance Dabney's distance = 765

Cabrina's distance = x

Dabney's distance = 765-x

The sum of their times is 11.5 hours, therefore

Cabrina's time Dabneys time = 11.5

Cabrina's time = x / 75

Dabney's time = (765-x) / 60

x / 75 (765-x) / 60 = 11.5

Lowest common denominator of 75 and 60 is 300, therefore we have:

330 * x / 75 300 * (765-x) / 60 = 300 * 11.5

4 * x 5 * (- x 765) = 3450

4 * x - 5 * x 3825 = 3450

x = 375

Replacing:

Cabrina's time = 375/75 = 5 hours took

Dabney's time = (765-375) / 60 = 6.5 hours took

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3 years ago

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