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Georgia [21]
3 years ago
12

What is the product of the binomials below? (3x+6)(4x+2)

Mathematics
2 answers:
uranmaximum [27]3 years ago
4 0

(3x+6) (4x+2)

3x          6

12x^2       24x              4x

6x           12                   2

I used a punnet square type deal here.

12x^2 + 24x + 6x + 12

12x^2 + 30x+12               <------------- Answer

RUDIKE [14]3 years ago
3 0

Answer:

7x (times) 8

Step-by-step explanation:

(3x+6)(4x+2)

(3x + 4x)(6 + 2)

7x (times) 8

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Xpressions
zlopas [31]
you do parentheses first so 32-8=24
4+2=6



answer 24=6
8 0
3 years ago
Please help meee i need asap
NARA [144]

Answer:

WTH is that bro, If I had to answer this between a life or death situation I'd die

7 0
3 years ago
Read 2 more answers
{[20/(8+2)]^6+6}/(4^2/2)
Naddika [18.5K]
So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)
7 0
3 years ago
Read 2 more answers
1. Find the value of x. *
oksano4ka [1.4K]
Forgive me if I’m wrong. 25?
4 0
3 years ago
Read 2 more answers
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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