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Alina [70]
4 years ago
12

6 Use the given property of equality to complete each statement.

Mathematics
1 answer:
VMariaS [17]4 years ago
8 0

Answer:

  b+3 = 12

Step-by-step explanation:

The transitive property tells you that two things equal to the same thing are equal to each other

  a+5 = b+3

  a+5 = 12

  b+3 = 12 . . . . transitive property

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If a+ar =b+r the value of an item of b and r can be expressed as
Dennis_Churaev [7]
a+ar=b+r\\
a(1+r)=b+r\\
a=\dfrac{b+r}{1+r}
5 0
3 years ago
Math Help
Slav-nsk [51]

Answer:

exponential growth function

Step-by-step explanation:

exponential growth function because the numbers are positive so it'll go up idk the number but until somebody else answers you can do process of elimination


3 0
3 years ago
Read 2 more answers
PLEASEEEE HELPPP MEEE WITHHH THISS QUESTIONN PLEASEEE!!!!<br> I NEED A GREAT EXPLANATION PLEASEE!!!!
ipn [44]

The diagonal of a rhombus divides it into two congruent isosceles triangles.

So ∠CBD ≅ ∠CDB

∠CBD + ∠CDB + 68 = 180

2∠CBD = 180 - 68 = 112

∠CBD = 56

We also have

∠BDE + ∠E + ∠DBE = 180

∠DBE = 180 - 73 - 36 = 71

∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15

Answer: ∠EBC = 15 degrees

4 0
3 years ago
How to do this because I don't know my class work
salantis [7]
I assume the answer is 1/4
5 0
4 years ago
Ms. wilson draws a model of the factorization of a polynomial with integer factors. her model is partially complete. a 2-column
lana [24]

The equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)

<h3>How to determine the equation of the model?</h3>

The partially completed model is given as:

    |  n

    |  n²

5   | 5n  |  40

By dividing the rows and columns, the complete model is:

    |  n    | 8

n   |  n²  |  8n

5   | 5n  |  40

Add the cells, and multiply the leading  row and columns

n² + 8n + 5n + 40 = (n + 8)(n + 5)

This gives

n² + 13n + 40 = (n + 8)(n + 5)

Hence, the equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)

Read more about polynomials at:

brainly.com/question/4142886

#SPJ4

7 0
2 years ago
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