Y = x + 1
y = 2x - 1
basically we r going to sub in one y for another
x + 1 = 2x - 1
1 + 1 = 2x - x
2 = x
now we sub 2 in for x in either of the original equations to find y
y = x + 1
y = 2 + 1
y = 3
so ur solution is (2,3)
1/6 yards. All you have to do is add the two upper numbers (numerator) ans then subtract 6/6 - 5/6
The answer to your question would be 'A'
Answer:
If PQRS is a parallelogram with two adjacent congruent sides, then it must be a rhombus. A rhombus is a parallelogram characterized by having all sides congruent. Therefore, the adjacent sides must be congruent as well.