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uysha [10]
3 years ago
12

Determine the validity of the following argument: For students to do well in a discrete mathematics course, it is necessary that

they study hard. Students who do well in courses do not skip classes. Students who study hard do well in courses. Therefore students who do well in a discrete mathematics course do not skip class.
Mathematics
1 answer:
Vinvika [58]3 years ago
5 0

Answer: True

Step-by-step explanation:

Let p= Students who do well in course do not skip class

q= Student who study hard do well in course

So p^q= Student who study hard and who do well in course do not skip class.

If p= true and q=true then p^q= true by discrete maths.

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2. The functions ???? and ???? represent the population of two different kinds of bacteria, where x is the time (in hours) and ?
klio [65]

Answer:

(a) Bacterial 1 had a faster rate of growth.

(b) The population of f(x) always exceed the population of g(x). In other words, population of g(x) cannot exceed the population of f(x).

Step-by-step explanation:

Consider the given functions are

f(x)=2x^2+7

g(x)=2x

where, x is the time (in hours) and f(x) and g(x) are the number of bacteria (in thousands).

(a)

The rate of change of a function f(x) on [a,b] is

m=\frac{f(b)-f(a)}{b-a}

Rate of change between third and sixth hour of first function is

m_1=\frac{f(6)-f(3)}{6-3}

m_1=\frac{(2(6)^2+7)-(2(3)^2+7)}{6-3}

m_1=\frac{79-25}{3}

m_1=\frac{54}{3}

m_1=18

Rate of change between third and sixth hour of second function is

m_2=\frac{g(6)-g(3)}{6-3}

m_2=\frac{2(6)-2(3)}{6-3}

m_2=\frac{12-6}{3}

m_2=\frac{6}{3}

m_2=2

Since m_1>m_2, therefore bacterial 1 had a faster rate of growth.

(b)

The initial population of f(x) is 7 and it increases exponentially.

The initial population of g(x) is 0 and it increases linearly.

It means population of f(x) always exceed the population of g(x).

In other words, population of g(x) cannot exceed the population of f(x).

8 0
3 years ago
Help me with math please :(
zlopas [31]
Answer is C ...................
8 0
3 years ago
PLEASE HELP Find the area of the rectangle, to the nearest hundredth, with a base of 5 inches and a height = 2.5 inches. Type a
il63 [147K]

Answer:

The area of a rectangle with a width of 5 inches, and a height of 2.5 inches, would have an area 12.5 inches!

Step-by-step explanation:

To find the area of a rectangle, simply multiply the width (W) by the length (L) to find the area (A) of the rectangle.

A = W x L

A = 5 inches x 2.5 inches

A = 12.5 inches

Hope this helps! :)

5 0
3 years ago
Please help. 10 points. Please do not guess. Guesses will be reported.
Alex73 [517]

The inscribed angle theorem says that

m\angle CAB=\dfrac12m\angle COB

Triangle AOC is isosceles because both AO and CO are radii of the circle and have the same length. This means angles CAO and ACO have the same measure and are congruent.

Angles ACO and COD are congruent because they form an alternating interior pair between the parallel lines AC and OD.

Taking all these facts together, we have

m\angle COB=2m\angle COD

and since angle COB is made up of angles COD and DOB, these angles must be congruent, and so the arcs they subtend (CD and DB, respectively) must also congruent.

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3 years ago
Crystal earns $5.50 per hour mowing lawns. A. Write a rule to describe how the amount of money m earned is a function of the num
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She earns $20.625 in 3 hours and 45 mins
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4 years ago
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