Solve 12^x-2=20 round to the nearest ten-thousandth? help, please!

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

The answer to the equation: 12^x-2=20 round to the nearest ten-thousandth is:

$x=1.2440$

Step-by-step explanation:

We need to find x of the equation (1)

$12^x-2=20$

Now, the number two goes to the other side of the equation to add

$12^x=20+2\\12^x=22$

We need to multiply by logarithm on both sides of the equation

$Log(12^x)=Log(22)$

Using the properties of the logarithms, we know:

$x*Log(12)=Log(22)\\x=\frac{Log22}{Log12}$

$x=1.2439$

The nearest ten-thousandth is:

$x=1.2440$

babymother [125]3 years ago

3 0

12^x - 2 = 20
12^x = 22
x log 12 = log 22
x = (log 22)/(log 12)

The rest is a calculator exercise. Use any base log you like, as long as both are the same base. (The right side is really the base-12 logarithm of 22, but nobody has a base-12-log key on their calculator.)

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Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int

navik [9.2K]

Answer: $28\ cubes$

Step-by-step explanation:

The volume of a cube can be found with this formula:

$V_{(c)}=s^3$

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

$V_{rp}=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

$V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3$

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

$1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}$

Then the volume of the shipping box is:

$V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3$

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

$\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28$