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Travka [436]
2 years ago
6

Solve 12^x-2=20 round to the nearest ten-thousandth? help, please!

Mathematics
2 answers:
luda_lava [24]2 years ago
7 0

Answer:

The answer to the equation: 12^x-2=20 round to the nearest ten-thousandth is:

x=1.2440

Step-by-step explanation:

We need to find x of the equation (1)

12^x-2=20

Now, the number two goes to the other side of the equation to add

12^x=20+2\\12^x=22

We need to multiply by logarithm on both sides of the equation

Log(12^x)=Log(22)

Using the properties of the logarithms, we know:

x*Log(12)=Log(22)\\x=\frac{Log22}{Log12}

x=1.2439

The nearest ten-thousandth is:

x=1.2440

babymother [125]2 years ago
3 0
12^x - 2 = 20
12^x = 22
x log 12 = log 22 
x = (log 22)/(log 12) 

The rest is a calculator exercise. Use any base log you like, as long as both are the same base. (The right side is really the base-12 logarithm of 22, but nobody has a base-12-log key on their calculator.)
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enot [183]
Hopes this helps if it don’t than sorry:

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3 0
3 years ago
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31 cars are in a race. In how many different ways can cars finish in order in the top 4 positions?
cupoosta [38]

Answer:

755,160 ways

Explanation:

We're told that 31 cars are in a race.

Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;

31\times30\times29\times28=755,160\text{ ways}

8 0
1 year ago
Solve for x: 5/8=x-1/9<br><br> A. 37/8<br> B. 23/4<br> C. 11/2<br> D. 53/8
Vesna [10]

Answer:

53/72

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5/8 = x - 1/9

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5/8 + 1/9 = x

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3 years ago
What is the estimate of -4.2 - (-2.9). Show your work
irakobra [83]

Answer:

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-4.2-(-2.9)

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-1

5 0
3 years ago
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