<span>in
2007, the world's population reached 6.7 billion was increasing at a rate of
1.2% per year. Assume that the growth rate remains constant.
Generalize the expression for the world's population for t years since 2007 is:</span>
<span>P(t)
= 6,700,000 (1.012)^t </span>
Answer:
a) increase by 4%
b) $ 98.54
Step-by-step explanation:
The given function is
We can rewrite this function as
Therefore the cost of the chemical increase over time by 4%
b) We want to find how much an ounce of the chemical cost in 2018.
Since 2010 to 2018, 8 years have passed.
We substitute x=8 to get:
Answer:
p = 2 and q = 14
Step-by-step explanation:
Evaluate f(g(x)) by substituting x = g(x) into f(x), that is
f(px + 4)
= 3(px + 4) + p = 3px + 12 + p
f(g(x)) = 3px + 12 + p and f(g(x)) = 6x + q
Equating the 2 expressions gives
3px + 12 + p = 6x + q
Compare the coefficients of like terms and the constant term
For the 2 expressions to be equal then
3p = 6 ⇒ p = 2 , and
q = 12 + p = 12 + 2 = 14
The correct answer is:
(x,y) - (x + 4, y - 3)
I hope this has helped you.
Any doubts or questions, please ask in comments and I’ll happily assist you.
Answer:
6/18=1/3=2/6=3/9=4/12=5/15
