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tatuchka [14]
3 years ago
12

Sandy has 16 roses, 8 daisies, and 32 tulips. She wants to arrange all the flowers in bouquets. Each bouquet has the same number

of flowers and the same type of flower. What is the greatest number of flowers that could be in a bouquet?
Mathematics
2 answers:
Korvikt [17]3 years ago
8 0
The greatest number of flowers that could be in a bouquet is 8.
lukranit [14]3 years ago
7 0
Each bouquet could have 8 flowers because 8 is the greatest common factor.
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PLZ HELP ASAP AREA OF A SECTOR
timama [110]
The relationship of arcs is:
 S '/ S = ((1/9) * pi * r) / (2 * pi * r)
 Rewriting we have:
 S '/ S = ((1/9)) / (2)
 S '/ S = 1/18
 Therefore, the area of the shaded region is:
 A '= (S' / S) * A
 Where A: area of the complete circle:
 Clearing we have:
 A = (A ') / (S' / S)
 Substituting:
 A = ((1/2) pi) / (1/18)
 A = ((18/2) pi)
 A = (9pi)
 Answer:
 The area of the circle is:
 
A = (9pi)
4 0
3 years ago
Find the average rate of change of f(x) = -x² + 5x+2 from x=3 to x=6.
ivolga24 [154]

9514 1404 393

Answer:

  -4

Step-by-step explanation:

The points at the ends of the interval are ...

  (3, f(3)) = (3, 8)

  (6, f(6)) = (6, -4)

The slope is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (-4 -8)/(6 -3) = -12/3 = -4

The average rate of change is -4.

6 0
3 years ago
Which conditional has a true converse? Select all that apply
Andrej [43]
The answer is b I hope this helps
3 0
3 years ago
A randomized controlled study was designed to test whether regular drinking of cranberry juice can prevent the recurrence of uri
Kamila [148]

Answer:

1. The chi-squared statistic = 10.36

The degrees of freedom = 17

The p-value for the test = 0.89

2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90

Step-by-step explanation:

1. The Chi squared test is given as follows;

\chi ^{2} = \sum \dfrac{\left (Observed - Expected  \right )^{2}}{Expected  }

Therefore,

                              UTI   No UTI    %     Total

Cranberry juice       8           42      84     50

Lactobacillus          19          30       61     49

Control                    18          30      60    50

The chi-squared statistic is given as follows;

\chi ^{2} = \dfrac{\left (8- 18\right )^{2}}{18} +  \dfrac{\left (42 - 30\right )^{2}}{30} = 10.36

The chi-squared statistic = 10.36

The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18

With the aid of the calculator we find the p value as p as follows;

p = 0.9 - \dfrac{10.36 - 10.085}{12.972 - 10.085} \times (0.9 - 0.75)

The p-value for the test = 0.89  

2. The range of the p-value from the Chi squared table is given as follows;

0.75 < p-value < 0.90.

5 0
3 years ago
Given the system of equations, what is the solution?
fredd [130]

The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1.

Step-by-step explanation:

The given is,

           x+3y=5......................................(1)

           x-3y=-1....................................(2)

Step:1

         By elimination method,

        Subtracting Equations (1) and (2),

                     x+3y=5

                     x-3y=-1

             ( - )

           ( x-x ) + ( 3y+3y ) = ( 5 +1 )

                                       6y = 6

                                         y = 1

Step:2

        Substitute the value of y in equation (1),

                             x+3y=5

                       x + ( 3 × 1 ) = 5

                                      x = 5-3

                                      x = 2

Step:3

        Check for Solution,

        Substitute the values of x and y in Eqn (1),

                                  x+3y=5

                           2 + ( 3 × 1 ) = 5

                                         5 = 5

Result:

       The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.

7 0
3 years ago
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