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mario62 [17]
3 years ago
9

What is 3 2/3 minus 1 1/4

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

Answer: 2  5/12

3⅔ - 1¼ = 2  5/12

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How to convert 264 yds/1 s to mi/day?
dusya [7]

Answer:

12,960\ \frac{miles}{day}

Step-by-step explanation:

we know that

1\ mile=1,760\ yards

To convert yards to miles multiply by 1/1,760

1\ hour=3,600\ seconds

1\ day=24\ hours

so

(24)3,600=86,400

1\ day=86,400\ seconds

To convert seconds to day multiply by 1/86,400

In this problem we have

264\ \frac{yd}{sec} =264\ \frac{(1/1,760)}{(1/86,400)}=264\ (\frac{86,400}{1,760})=12,960\ \frac{miles}{day}

7 0
4 years ago
Here is a number line<br> Please answer will give brainliest
andreev551 [17]

Answer:

-3<n<=5

Step-by-step explanation:

This is because the coloured circle on the number line means that the number is less than or equal to 5

4 0
3 years ago
Find the missing length of the right triangle
LiRa [457]
Is their suppose to be a picture ?
8 0
4 years ago
Find the volume of the box. Use the formula V = lwh. Rectangular box with sides x plus 2, 2x minus 1, and 3x plus 1.
nata0808 [166]
I got.......6x^3 + 5x^2 - 3x - 2................not sure though
3 0
3 years ago
To boost the growth of a crop, a farmer decided to use different combinations of three fertilizers, A, B, and C. The first combi
Dvinal [7]

Answer:

The answer is explained below

Step-by-step explanation:

Let x be the price of fertilizer A, y be the price of fertilizer B, and z be the price of fertilizer C

The first combination  costs $384 and consists of 6 liters of fertilizer A, 5 liters of fertilizer B, and 3 liters of fertilizer C. The first combination is given by the equation:

6X + 5Y + 3Z = 384

The second combination consists of 10 liters of A, 2 liters of B, and 6 liters of C, and it costs $516. The second combination is given by the equation:

10X + 2Y + 6Z = 516

The last combination consists of 4 liters of A, 8 liters of B, and 2 liters of C,  with a cost of $368. The last combination is given by the equation:

4X + 8Y + 2Z = 368

In Matrix form it can be represented as:

\left[\begin{array}{ccc}6&5&3\\10&2&6\\4&8&2\end{array}\right]\left[\begin{array}{c}X\\Y\\Z\end{array}\right]=\left[\begin{array}{c}384\\516\\368\end{array}\right]

\left[\begin{array}{c}X\\Y\\Z\end{array}\right]=\left[\begin{array}{ccc}6&5&3\\10&2&6\\4&8&2\end{array}\right]^{-1}\left[\begin{array}{c}384\\516\\368\end{array}\right]\\\\\left[\begin{array}{c}X\\Y\\Z\end{array}\right]=\left[\begin{array}{ccc}1.5714&-0.5&-0.857\\-0.142&0&0.2142\\-2.571&1&1.3571\end{array}\right]\left[\begin{array}{c}384\\516\\368\end{array}\right]\\\\\left[\begin{array}{c}X\\Y\\Z\end{array}\right]=\left[\begin{array}{c}30\\24\\28\end{array}\right]

Therefore:

X = $30, Y = $24, Z = $28

The price of fertilizer A = $30 per liter, The price of fertilizer B = $24 per liter and The price of fertilizer c = $28 per liter

7 0
3 years ago
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