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Given segment AC and point B that lies on AC,

ololo11 [35]

The total length of the segment AC is the sum of AB and CB, which gives, CB = 9

<h3>How can the length of CB be found?</h3>

The given parameters are;

AC = 17
AB = 32 + 3•x
CB = 57 + 6•x

Required: CB

Solution:

AC = AB + CB by segment addition property

Therefore;

AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x

17 = 89 + 9•x

$x = \frac{17 - 89}{9} = - 8$

CB = 57 + 6•x = 57 + 6 × (-8) = 9

Therefore;

CB = 9

Learn more about segment addition postulate here: brainly.com/question/1721582

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8 0

2 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

12x + 4 divided by 4 plus 20x + 5 divided by 5

Rasek [7]

12x + 4 ➗ 4 + 20x + 5 ➗ 5

1. PEMDAS (order of operations) solve the division problems

(4 divided by 4 & 5 divided by 5)
12x + 1 + 20x + 1

2. Swap around the order of operations as commutative property states that you can swap the order of an addition problem and get the same answer.

12x + 20x + 1 + 1

3. Add like terms

32x + 2

This is the most simplified answer you could get as you can not add 32x and 2 as they are not like terms.

6 0

2 years ago

What does x and y equal

GaryK [48]

Answer:

x=5, y=-3

Step-by-step explanation:

we can find the answer by plugging in x=3y+14 to the second equation

5(3y+14)-2y=31

simplify

15y+70-2y=31

13y=-39