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erastova [34]
3 years ago
5

Bob sold 5 toaster ovens and 3 blenders for $500. if a blender is $20 less than a toaster oven, how much is a blender?

Mathematics
2 answers:
Harrizon [31]3 years ago
7 0
The answer would be $50 per blender. 
To explain the way I did it --
Toaster ovens - 70 * 5 = 350
70 - 20 = 50
Blenders - 50 * 3 = 150
350 + 150 = 500
dimaraw [331]3 years ago
7 0
The total cost is $500 and this is distributed between 5 toasters and 3 blenders. Let's assign "t" for the price of a toaster and "b" for the price of a blender.
500=5t+3b
we know that a blender costs $20 less than a toaster which is expressed by "b=t-20", so instead of "b" we can write "t-20" to represent the price of a blender
500=5t+3(t-20)
500=5t+3t-60 distribute the 3
500+60=5t+3t-60+60 add 60 to both sides
560=8t add like terms
560/8=8t/8 divide both sides by 8
70=t 
therefore a toaster costs $70
We can then substitute 70 into the "b=t-20" expression to find the price of a blender:
b=70-20
b=50
therefore, a blender costs $50
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Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

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