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Nata [24]
4 years ago
9

Will mark brainliest and 15 points :)

Mathematics
1 answer:
Vilka [71]4 years ago
7 0
The answer is the last one. The values are equal. The first equation is y=4x-3. If you plug in x=2 you get y=4(2)-3 which is 5. For the second one, it says an initial value of 5 and the y value does not change, so the value of this equation is always 5. Therefore they are both 5 when x=2 so they are equal when x=2.
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\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{\LARGE Line B}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{-1 -1}{4 +0}\implies -\cfrac{1}{2}

keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.

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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

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that means ~

\qquad \sf  \dashrightarrow \: y \degree = 163 \degree

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