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SCORPION-xisa [38]
3 years ago
7

What is the slope of the line?-21/212

Mathematics
1 answer:
photoshop1234 [79]3 years ago
4 0
Going to be number two becaus
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Given the function below, what value will result in f(x)=10?<br> f(x)=1/2x+8
nignag [31]
10 = 1/2x + 8
2 = 1/2x
X = 4
5 0
3 years ago
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The area of a rectangular front yard is, 180 square feet find the length of the front yard if the width is 15 feet
VMariaS [17]
Area = length x width
180 = L x 15
L = 180/15
Length = 12 feet
6 0
2 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The​ plate, including the bound
rjkz [21]

Answer:

We have the coldest value of temperature T(\frac{3}{4},0) = -9/16. and the hottest value is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x

Let's take the partials derivatives.

T_{x}(x,y)=2x-\frac{3}{2}=0

T_{y}(x,y)=4y=0

So, we can find the critical point (x,y) of T(x,y).

2x-\frac{3}{2}=0

x=\frac{3}{4}

4y=0

y=0

The critical point is (3/4,0) so the temperature at this point is: T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})

T(\frac{3}{4},0)=-\frac{9}{16}    

Now, we need to evaluate the boundary condition.

x^{2}+y^{2}=1

We can solve this equation for y and evaluate this value in the temperature.

y=\pm \sqrt{1-x^{2}}

T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x  

T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2

Now, let's find the critical point again, as we did above.

T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0            

x=-\frac{3}{4}    

Evaluating T(x,y) at this point, we have:

T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2  

T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}

Now, we can see that at point (3/4,0) we have the coldest value of temperature T(\frac{3}{4},0) = -9/16. On the other hand, at the point -(3/4),\frac{\sqrt{7}}{4}) we have the hottest value of temperature, it is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

I hope it helps you!

4 0
2 years ago
Find the value of the expression. (6.885−0.365)÷2+1.44.
EleoNora [17]

Answer:

4.7

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4 0
3 years ago
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What is the simplified form of the following expression? 4/7^3
timofeeve [1]
If your question is :
\frac{4}{7^3}

Then the answer is:
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If your question is:
(\frac{4}{7}) ^{3}

Then the answer is:
\frac{4*4*4}{7*7*7} =  \frac{64}{343}
6 0
3 years ago
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