1) yes
2) x=-4,y=-7
3) x= -3, y=4
4) x= -1, y=2
5) x= -5, y=-8
So we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2
the factors of a poly equation that passes through r1,r2,r3 is
(x-r1)(x-r2)(x-r3)
so
r1=-1
r2=0
r3=2
f(x)=(x-(-1))(x-0)(x-2)
f(x)=(x+1)(x)(x-2)
f(x)=x³-x²-2x
leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right
yah
actually that looks like the exact graph
both
f(x)=(x+1)(x)(x-2)
and
f(x)=x³-x²-2x
are correct
Answer:
56.25
Step-by-step explanation:
If x is 0 then I think it would be the 3 to the second power and that is 9. Because 0 + 9 = 9. Correct me if I’m wrong!
Answer:
-(6ap³)
Step-by-step explanation:
We have to find the quotients of
We take the common 2a² p from the numerator
= 
= -(6ap³)
Therefore, the quotient after division will be -(6ap³)
