Answer:
y = -7x + 57
Step-by-step explanation:
If the line is parallel, it will have the same slope. So, this line will also have a slope of -7.
Use y = mx + b, plug in the slope and given point, and solve for b:
y = mx + b
-6 = -7(9) + b
-6 = -63 + b
57 = b
Plug in the slope and y intercept into y = mx + b:
y = mx + b
y = -7x + 57
So, the equation is y = -7x + 57
We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors.
A) The amount financed is the purchase amount less the down payment.
$2,574.54 -574.54 = $2000.00
B) The finance charge is the total of payments less the amount financed.
18*$121.00 -2000.00 = $178.00
C) The APR is calculated by a financial calculator to be 10.96%.
Answer:
![a=\frac{2S -2v_ot-2s_o}{t^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2S%20-2v_ot-2s_o%7D%7Bt%5E2%7D)
Step-by-step explanation:
We have the equation of the position of the object
![S = \frac{1}{2}at ^2 + v_ot+s_o](https://tex.z-dn.net/?f=S%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%20%5E2%20%2B%20v_ot%2Bs_o)
We need to solve the equation for the variable a
![S = \frac{1}{2}at ^2 + v_ot+s_o](https://tex.z-dn.net/?f=S%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%20%5E2%20%2B%20v_ot%2Bs_o)
Subtract
and
on both sides of the equality
![S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o](https://tex.z-dn.net/?f=S%20-v_ot-s_o%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%20%5E2%20%2B%20v_ot%2Bs_o%20-%20v_ot-%20s_o)
![S -v_ot-s_o = \frac{1}{2}at ^2](https://tex.z-dn.net/?f=S%20-v_ot-s_o%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%20%5E2)
multiply by 2 on both sides of equality
![2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2](https://tex.z-dn.net/?f=2S%20-2v_ot-2s_o%20%3D%202%2A%5Cfrac%7B1%7D%7B2%7Dat%20%5E2)
![2S -2v_ot-2s_o =at ^2](https://tex.z-dn.net/?f=2S%20-2v_ot-2s_o%20%3Dat%20%5E2)
Divide between
on both sides of the equation
![\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}](https://tex.z-dn.net/?f=%5Cfrac%7B2S%20-2v_ot-2s_o%7D%7Bt%5E2%7D%20%3Da%5Cfrac%7Bt%5E2%7D%7Bt%5E2%7D)
Finally
![a=\frac{2S -2v_ot-2s_o}{t^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2S%20-2v_ot-2s_o%7D%7Bt%5E2%7D)
18 - 22 + 5x(66:3)
= 18 - 22 + 5x22
= -4 + 110
= 77
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