The solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3
<h3>What is a quadratic equation?</h3>
Any equation of the form where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
We have a quadratic equation:
x² + 2x - 2 = 0
x² + 2x + 1 - 1 - 2 = 0
(x + 1)² - 3 = 0
(x + 1)² = 3
x + 1 = ± √3
x = -1 ± √3
Thus, the solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3
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No as the Pythagorean theorem does not apply
B5 = -1 x (2 ^ 5 - 1)
B5 = -1 x (2 ^ 4)
B5 = -1 x 16
B5 = -16
Check the picture below, so the park looks more or less like so, with the paths in red, so let's find those midpoints.
now, let's check the other path, JM and KL
so the red path will be
we know that θ is in the III Quadrant, and let's recall that on the III Quadrant sine and cosine are both negative, and since tangent = sine/cosine, that means that tangent is positive. Let's also keep in mind that tan(π) = sin(π)/cos(π) = 0/-1 = 0.
well, the hypotenuse is just a radius unit, so is never negative, since we know sin(θ) = -(5/13), well, the negative number must be the 5, so is really (-5)/13.