Question

Determine the number of possible solutions for a triangle with B = 37, a= 32, and b = 27.

Answer 1

Answer:

1

Step-by-step explanation:

$\frac{b}{sin B} =\frac{a}{sin A} \\\frac{27}{sin 37} =\frac{32}{sin A} \\\frac{32}{27} sin 37=sin A\\A=sin ^{-1} [\frac{32}{27} sin 37] \approx 45.5^\circ$

C=180-(37+45.5)=180-82.5=97.5°

one solution.