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Kay [80]
3 years ago
9

7. Find DE ( Triangle mid-segment theorems)

Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

45 units

Step-by-step explanation:

See the given diagram with the question here.

The point D and point E are the midpoints of line segments AC and BC respectively.

Therefore, the length of the line joining points D and E will be half of length AB.

Now, given that AB = 11x - 25 and DE = 4x + 1.

Hence, ( 11x - 25 ) = 2 ( 4x + 1 )

⇒ 3x = 33

⇒ x = 11

Therefore, length DE = 4x + 1 = 4 ( 11 ) + 1 = 45 units. (Answer)

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What are the solutions to the system of equations graphed below?
Shtirlitz [24]

Answer:

(- 2, - 5 ) and (2, 0 )

Step-by-step explanation:

the solution to the graphed system is at the points of intersection of the 2 graphs.

the graphs intersect at (- 2, 5 ) and (2, 0 ) , thus

the solutions are (- 2, 5 ) and (2, 0 )

7 0
2 years ago
PLEASE ANSWER DUE IN 20 MIN
professor190 [17]

Answer:

Read

Step-by-step explanation:

Mean: add all the values and divide by the number of values

Median: when in order from least to greatest, the middle value

Mode: The value that ocoours most often

5 0
3 years ago
if a tv has a diagonal measurement of 55 and a height of 30, what is the tvs width? round to the nearest whole number
Sati [7]

Answer:

  46

Step-by-step explanation:

The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.

__

<h3>Pythagorean theorem</h3>

The relation between the leg lengths (a, b) and the hypotenuse (c) is ...

  c² = a² +b²

Solving for b gives ...

  b = √(c² -a²)

<h3>application</h3>

In this problem, we have c=55 and a=30. Then the width of the TV is ...

  b = √(55² -30²) = √(3025 -900) = √2125

  b ≈ 46.098

The width of the TV is about 46.

7 0
2 years ago
(- 3/8) divided by 5/9
Levart [38]
Do you want the exact form or decimal form?
4 0
3 years ago
Help me to answer this pls​
zepelin [54]

The 6 angles with vertex P are:

  1. Angle APB
  2. Angle APC
  3. Angle APD
  4. Angle BPC
  5. Angle BPD
  6. Angle CPD

The letter P must be in the middle since this location is the vertex. Something like angle BPA is the same as angle APB. We can swap the order of the outer letters without any change to the angle itself. Effectively, this means each angle has two possible names.

8 0
2 years ago
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