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Elena L [17]
3 years ago
11

Colleen says she is thinking of a 4 digit number in which all the digits are the same. the value of the digit in the hundreds pl

ace is 200. Describe the relationship between the values of the digits in the number.
Mathematics
1 answer:
Triss [41]3 years ago
3 0

Colleen says she is thinking of a 4 digit number in which all the digits are the same.

Since, the value of the digit in the hundreds place is 200. It means that one of the digit of the given number is 2.

Since, all the digits of a number are same.

Therefore, the number is 2222.

Now, we can expand 2222 = 2000+ 200 + 20 + 2

Hence, we can observe the relationship between the digits of the number that the number 2222 is expressed as the sum of the place value of each of the digit.

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olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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5 0
3 years ago
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Answer:

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----------------- = -----------------

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Step-by-step explanation:

I am assuming that by "sqrt(a)/sqrt(a)-2" you meant:

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-----------------

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3 0
3 years ago
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