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3 years ago

In ΔDFE, which trigonometric ratio has the same value as sin D?

Mathematics

2 answers:

DerKrebs [107]3 years ago

5 0

Hello,

sin (30°)= cos (60°)=1/2 (complementary angles)
sin D= cos E

Answer C

Makovka662 [10]3 years ago

3 0

Answer:

C. cos E

Step-by-step explanation:

We have been given a right triangle DEF. We are asked to find the trigonometric ratio, which has the same value as sin D.

We know that measure of angle F is 90 degrees as all angles of triangle add up-to 180 degrees. The side DE is hypotenuse of triangle DEF.

Let us find sin D for our given triangle.

$\text{Sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{Sin(D)}=\frac{\text{FE}}{\text{DE}}$

We know that cosine relates adjacent side of right triangle to hypotenuse.

$\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

We can see that FE is adjacent side of angle E, so:

$\text{Cos(E)}=\frac{\text{FE}}{\text{DE}}$

Therefore, cos E has the same value as sin D and option 'C' is the correct choice.

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Step-by-step explanation:

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Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

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