What is the product? (5r + 2)(3r − 4)

1 answer:

6 0

Distribute the first set of parenthesis

15r2−20r+6r−8
Combine like terms

15r2+(−20r+6r)−8
Simplify your answer

15r2−14r−8

*Answer is 15r^2−14r−8*

You might be interested in

A class consists of 13 boys and 10 girls. They want to elect officers so that the president and secretary are girls, and the vic

Viktor [21]

Answer:

10 boys and ten girls

Step-by-step explanation:

if there are 13 boys and 10 girls,and 3 boys dont participate,then there are 10 boys. making there an equal ammout of boys and girls.

not sure if this is what you were asking but if it was then i hope it helps

8 0

3 years ago

Image attachment below, Algebra 1 stuff

chubhunter [2.5K]

I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function.

The first batch of problems gave you the equation f(x) = $\frac{x}{2}$ + 3. Now, plug in the numbers given for s and solve.

1. f(5) = $\frac{x}{2}$ + 3 Plug in 5 for x
 = $\frac{5}{2}$ + 3 Make three into a fraction over 2
= $\frac{5}{2}$ + $\frac{6}{2}$ Add
= $\frac{11}{2}$

2. f(-4) = $\frac{x}{2}$ + 3 Plug in -4 for x
= $\frac{-4}{2}$ + 3 Divide -4 by 2
= -2 + 3 Add
= 1

For the next set, you have g(x) = x² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put the answers together to solve it.

g(4) = x² + 1 Plug in 4 for x
= 4² + 1 Square
= 16 + 1 Add
= 17

g(3) = x² + 1 Plug in 3 for x
= 3² + 1 Square
= 9 + 1 Add
= 10

Now, put the two together.

g(4) + g(3) = Substitute in the answers you just got.
17 + 10 = Add
= 27

4. g(-1) = x² + 1 Substitute in -1 for x
= (-1)² + 1 Square
= 1 + 1 Add
= 2

5. g(-6) = x² + 1 Plug in -6 for x
= (-6)² + 1 Square
= 36 + 1 Add
= 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7 Plug in -6 for x
= (-6)² + 7 Square
= 36 + 7 Add
= 43

k(4) = 4x - 5 Plug in 4 for x
= 4(4) - 5 Multiply
= 16 - 5 Subtract
= 11

Put the two answers into the final equation.

h(-6) + k(4) = Substitute in the answers you got
43 + 11 = Add
= 54

7. k(10) = 4x - 5 Plug in 10 for x
= 4(10) - 5 Multiply
= 40 - 5 Subtract
= 35

h(2) = x² + 7 Plug in 2 for x
= 2² + 7 Square
= 4 + 7 Add
= 11

Now, put those into the equation.

k(10) - h(2) = Plug in the answers you got
35 - 11 = Subtract
= 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
x² + 7 + 4x - 5 = Combine like terms (7 and -5)
x² + 2 + 4x = Reorder so the variables come first
= x² + 4x + 2

4 0

3 years ago

Read 2 more answers

What is the justification for each step in the solution of the equation?

Alexandra [31]

For this case we have the following equation:

$\frac{2}{3}x-\frac{1}{3}= 2 (x + 2)\\$