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OLga [1]
3 years ago
15

To pass a course with aa upper cc ​grade, a student must have an average of 7070 or greater. a​ student's grades on three tests

are 7070​, 7373​, and 6565. find what score the student must get on the next test to get aa upper cc averagenbsp or better. or better.
Mathematics
1 answer:
forsale [732]3 years ago
8 0
The sum of 70, 73, and 65 is 208. Adding a 72 to that equation makes the sum 280. The mean then becomes 70. The answer is 72.
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If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
krok68 [10]

Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

⇒ Tanx = {\frac{7}{25}}(\frac{25}{24} )

⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

7 0
3 years ago
2p^2 -1 =7 <br> Would appreciate some help thank you
SIZIF [17.4K]

Answer: p = 2

Step-by-step explanation:

To solve this problem, you first have to add 1 to each side of the equation, leaving you with 2p^2 = 8. Then you divide by 2 on both sides leaving you with p^2 = 4. After that, you take the square root of both sides, and because 4 is a perfect square, you get p = 2 as your final answer.

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Step-by-step explanation:

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Step-by-step explanation:

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