1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grin007 [14]
3 years ago
13

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.

Find the probability that an individual distance is greater than 218.00 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00 c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?
Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

Probability value from Z-Table:

P(x<218) = 0.92696

P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

You might be interested in
What is x given ABC~DBE.<br> Show your work
alexandr1967 [171]

x = 37.5 (or) \frac{75}{2}

Solution:

Given \triangle A B C \sim \triangle D B E

AC = 50, DE = 30, EC = 25, BE = x, BC = 25 + x

To find the value of x:

Property of similar triangles:

If two triangles are similar then the corresponding angles are congruent and the corresponding sides are in proportion.

$\frac{BE}{BC} =\frac{DE}{AC}

$\frac{x}{25+x} =\frac{30}{50}

Do cross multiplication, we get

50x=30(25+x)

50x=750+30x

Subtract 30x from both sides of the equation.

20x=750

Divide by 20 on both sides of the equation, we get

x = 37.5 (or) \frac{75}{2}

Hence the value of x is 37.5 or \frac{75}{2}.

5 0
3 years ago
A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
Naddik [55]

Answer:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

8 0
3 years ago
How do you completely factor 2^2-9
Maurinko [17]
Step 1. Simplify 2^{2} to 4

4-9

Step 2. <span>Simplify

</span>-5
<span>
Done! Your answer is </span>-5
5 0
3 years ago
Un trapèze a une aire de 39 cm2. Sa grande base
V125BC [204]

Answer:

A = bh/2

39 = b*3/2

39*2 = b*3/2 * 2

78 = b*3

78/3 = b*3/3

26 = b.

Alors, la grande base est 26 cm et le petit base serait 26/3 = 8.67 cm arrondi.

6 0
3 years ago
One benefit of cluster sampling is that it Group of answer choices
luda_lava [24]

Answer:

a. is effective for use in school research.

Step-by-step explanation:

Cluster sampling is the sampling whereby we pick random few sample from the population to serve as the sample population called cluster. This cluster usually have uniform characteristics among them.

The main advantage of cluster sampling is that it is effective school research because of its cheapness and doesn't require much resources during the sampling process.

The other options are not correct because Cluster sampling have High sampling error and its biased sample.

3 0
2 years ago
Other questions:
  • The cost of producing x pumpkin pies at a small bakery is given by c(x)=49+1.75x. Find the cost of producing 25 pies A. $74.00 B
    13·1 answer
  • If someone weighs 130 kilos what is the conversion in lbs
    15·1 answer
  • Simplify completely (x^2-15x+36)/(5x-60)
    7·1 answer
  • How do I find the domain and range of a function?
    6·1 answer
  • Determine the slope of the following equation: 2y -4x = 9
    8·1 answer
  • a car dealer needs to move 260 cars and a transport truck can hold 8 cars 1a: How many trucks will the car dealer need to transp
    10·1 answer
  • What is J=4rb solved for r?
    8·2 answers
  • What is the greatest common factor of 12a and 9a^2?<br><br>A) 9<br>B) 36<br>C) 3a<br>D) 12a^2
    13·2 answers
  • (14 POINTSS+ BRAINLIESTT)<br><br> How are food and oxygen made during the process of photosynthesis?
    15·2 answers
  • Find the value of x so that f (x)=7 <br> x=
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!