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3 years ago

8

Four more than a number is more than 13

1 answer:

Pepsi [2]3 years ago

8 0

X > 9 is the answer. This is the correct answer because you would subtract 4 from each side of the equation, which would leave X on one side and nine on the other. The inequality remains the same since you are not dividing at all by any negative numbers

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What is value of K? It's not multiple choice.

larisa86 [58]

Answer:

14

Step-by-step explanation:

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3 years ago

Which graphs below have a domain of all real numbers? Which have a range of all real numbers? Which are functions?

slava [35]

Answer:

Step-by-step explanation:

From the picture attached,

Graph (A)

Domain of the function : (-∞, ∞) or a set of real numbers

Range of the function : (-∞, ∞) or a set of real numbers

Graph (B),

Domain : (-∞, ∞) Or a set of real numbers

Range : (-∞, 6] Or x ≤ 6

Graph (C),

Domain : [-2, ∞) or x ≥ -2

Range : (-∞, ∞) Or a set of real numbers

Therefore, Graphs (A), (B) have the domain of all real numbers and Graph (C) has the range of all real numbers.

Since all the parabolas are not the functions,

Therefore, Graph (C) is not a function. Graphs (A) and (B) are the functions.

3 0

3 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Anastasy [175]

Answer:

$\frac{(a-b)^2+b^2}{a^2}$

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

$=\sqrt{(a-b-0)^2+(0-b)^2}$

$=\sqrt{(a-b)^2+b^2}$

Thus the area of the inner square = (side)²

$=(\sqrt{(a-b)^2+b^2})^2$

$=(a-b)^2+b^2\text{ square cm}$

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

$=\sqrt{(a-0)^2+0^2}$

$=\sqrt{a^2}=a$

Thus, the area of the outer square = (side)²

$=a^2\text{ square cm}$

Hence, the ratio of the area of the inner square to the area of the outer square

$=\frac{(a-b)^2+b^2}{a^2}$

4 0

3 years ago

Read 2 more answers

What is the value of (–4)–3?

son4ous [18]

Here you go. Good luck!

7 0

3 years ago

C is the midpoint of chord AB and D is the midpoint of arc AB.Given that AB=36 unit and CD=6 unit then What is the radius of cir

Anna71 [15]

Answer:

By power of a point, AC⋅CB=DC⋅CE. That is, 12⋅12=6⋅(2R–6).

Then, R=15.

5 0

3 years ago

Read 2 more answers