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7nadin3 [17]
3 years ago
12

I need help with my homework ASAP

Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0

Answer:

Step-by-step explanation:

you can either get to know this or you can easily change the grade. so dont stress your self too much. contact . @THEDARKDUDE on telegram

dezoksy [38]3 years ago
3 0

Answer:

Question #5 = 2/3

Question #6 = 14/15

Question #7 = 20<em> 3/16</em> or 323/16

Next question is

greater than

Last Question Is

less than .

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Expand and simplify (x+5)(x-2)
salantis [7]

Answer:

{x}^{2} - x - 12 = (x + 3)(x - 4)

{x}^{2} + 3x + 2 = (x + 2)(x + 1)

{x}^{2} + 3x - 10 = (x + 5)(x - 2)

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

{x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12

{x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2

{x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10

I am joyous to assist you anytime.

8 0
3 years ago
Mapping congruent Triangles
Snezhnost [94]
The answer is b so mark it down
7 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-10, -8) and (−8,−16)? Write your answer in simplest form.
Leto [7]

Answer:y=-8 x=2

-8/2 or -4

Step-by-step explanation:

3 0
3 years ago
Please i need help :( <br> What is the Y- intercept of the graph of the linear function ?
emmainna [20.7K]

Answer:

Looks like -6

Step-by-step explanation:

4 0
2 years ago
Consider the first five steps of the derivation of the Quadratic Formula.
lara31 [8.8K]

Answer:

Full proof below

Step-by-step explanation:

\displaystyle ax^2+bx+c=0\\\\ax^2+bx=-c\\\\x^2+\biggr(\frac{b}{a}\biggr)x=-\frac{c}{a}\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\biggr(\frac{b}{2a}\biggr)^2=-\frac{c}{a}+\biggr(\frac{b}{2a}\biggr)^2\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=-\frac{4ac}{4a^2}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=\frac{b^2-4ac}{4a^2}\\ \\x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

6 0
2 years ago
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