Answer:
tanx + cotx = 
Step-by-step explanation:
<u><em>Explanation</em></u>
Take R.H.S =
= 
= 
= 
= tanx + cotx
tanx + cotx =
They will need 2 moving trucks
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
10 * (1.025)^9 = 12,48
Maybe 12.49 depending on rounding.
