Which ordered pair would be a solution to the equation y = 2x -9?
2 answers:
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The degree is 3, the zeros are; 4, 2i, -2i and a point is (-48, 2)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
+5) <-- b value is zero
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
the equation of a line perpendicular to and passes through the point (-6,8) is
Step-by-step explanation:
We need to write equation of line perpendicular to and passes through the point (-6,8)
Since the line is in slope-inetercept form
the slope of line m = 0.25
As, the new line is perpendicular to the given line so, slopes of lines that are perpendicular are: slope = -1/slope1
So, slope will be -1/0.25 = -4
Now, finding y-intercept.
So, value of y-intercept b = 30
Now the equation of the required line having slope m= -4 and b =30 will be:
So, the equation of a line perpendicular to and passes through the point (-6,8) is
Keywords: Equation of line, slope-intercept form
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