All categories

2 years ago

Which of the following illustrates the truth value of the given conditional statement?

Mathematics

1 answer:

ivolga24 [154]2 years ago

6 0

Answer:

~p -> ~q

Step-by-step explanation:

A conditional statement in logic may be symbolized by the alphabets, p and q, It always contains an if - then statement.

There is always a logical connector in the statement with the symbol ->.

A conditional statement is false if the hypothesis is true and the conclusion is false.

The statement in the answer above reads in word; "if not p then not q".

You might be interested in

Value of the digit in the hundredths place .44

Firlakuza [10]

0.04 is the answer to this question

3 0

3 years ago

Mr Taylor brought back 180 Euros to the UK. The exchange rate was €1.2 to £1.

solong [7]

The answer is £150.

This could be calculated using proportion. If £1 is €1.2, how many £ is €180:
£1 : €1.2 = x : <span>€180
</span>x = £1 ÷ €1.2 × <span>€180</span>
x = £150

6 0

3 years ago

Someone help? I need to get this right!

Lelechka [254]

Answer:

I think the answer is b

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

$EV=\lambda*t=5*0.75=3.75$

8 0

2 years ago

write the equation of the line with the given slope and y-intercept ..slope is -2 and a y-intercept of 5

iragen [17]

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

Since you know:

m = -2

b = 5 Substitute/plug it into the equation

y = mx + b

y = -2x + 5

5 0

3 years ago