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saveliy_v [14]
3 years ago
12

I have a math problem can uou solve it?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
Probably not sorry ........
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A cube has a side length of 6 cm. What is the volume of the cube, in cubic centimeters ​
Lady_Fox [76]

Answer:

V=216cm³

Step-by-step explanation:

V=216cm³

3 0
3 years ago
Mrs. Clark's plant is 4/3 4 inches tall. It is 1/7 8 inches taller than Jimmy's plant. How tall is Jimmy's plant? Enter your ans
White raven [17]

Answer:

克拉克夫人的植物高 4/3 4 英寸。它比吉米的植物高 1/7 8 英寸。何

7 0
2 years ago
The surface area of the prism below is 264 square units . Find the missing dimensions of this prism. ( picture is in the picture
nignag [31]

Answer:

The missing dimension is 4 units.

Step-by-step explanation:

In the given prism,

Of all the surfaces,

There are three rectangular surfaces and two triangular surfaces

<h2>Analyzing areas of rectangular surfaces:</h2>

1)The two rectangles with dimensions of 15 units and 5 units:

The area of each rectangle = Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 5 units.

Area of each rectangle = 15\times 5 ;

Area of each rectangle = 75 square units.

Sum of areas of the two rectangles = 2\times 75

Sum of areas of the two rectangles = 150 square units (equation 1)

2) The rectangle with the dimensions 15 units and 6 units:

The area of thus rectangle=  Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 6 units.

Area of the rectangle = 15\times 6 ;

Area of the rectangle = 90 square units. (equation 2)

From equation 1 and equation 2,

Therefore sum of areas of all rectangles in the prism = 150 + 90

Sum of areas of rectangles = 240 square units.

We also know,

Total surface area of the prism = Sum of areas of triangles + Sum areas of rectangles

Given, Total surface area of prism = 264 square units.

Therefore from the formula,

Sum of areas of triangles = Total surface area - sum of areas of reactangles

Sum of areas of triangles = 264 - 240

Sum of areas of triangles = 24 square units. (equation 3)

Let the missing dimension be 'h units'

<h2>Calculating sum of areas of triangles:</h2>

From diagram,both triangles are congruent,hence have the same area

Area of a triangle = \frac{1}{2}\times base\times height

From diagram,

Base = 6 units,

Height = h units.

Area of a triangle =\frac{1}{2}\times 6\times h = 3h square units.

Sum of the areas of both triangles = 3h+3h = 6h square units.

Using equation 3, we get

6h = 24;

h = \frac{24}{6}

Therefore,

h = 4 units.

Therefore,

The missing dimension is 4 units.

4 0
3 years ago
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My name is Ann [436]

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7 0
3 years ago
What is negative one / 3 plus the √10
marysya [2.9K]

Answer: 10 1/9

Step-by-step explanation:

-\frac{1}{3} + \sqrt{10}\\  \sqrt{10} ^{2} +(-\frac{1}{3})^{2}\\  10+\frac{1}{9} \\\\10 \frac{1}{9}

7 0
3 years ago
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