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Nikitich [7]
2 years ago
10

What is the solution set for the open sentence with the given replacement set?

Mathematics
1 answer:
olganol [36]2 years ago
7 0

Answer:

6

Step-by-step explanation:

2x + 7 = 19

     -7     -7

2x = 12

12/2 = x

6 = x

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3x + 2 = 14 what number makes this true?<br> A. 1<br> B. 2<br> C. 4<br> D. 6
Ksenya-84 [330]

Answer:

4

Step-by-step explanation:

3*4+2=14

12+2=14

14=14

5 0
3 years ago
Read 2 more answers
24=12 18=9 14=7 8=4 6=?
BartSMP [9]
Each pair of numbers gives a value then another value that is 1/2 of the first. So the answer would be

6 = 3
5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIST <br><br> Write an equation in Standard Form that has roots -4 and 7.
Misha Larkins [42]

Answer:

x^{2} -3x-28

Step-by-step explanation:

To find this equation in standard form, first, write it in factored form. This looks like y=(x+4)(x-7). Then, multiply the polynomials using the FOIL (First, Outside, Inside, Last) method.

  1. Following the FOIL method, you should multiply the first terms in each binomial, x*x, which equals x^{2}.
  2. Then, the outside terms, x*-7. This equals -7x.
  3. Next, the inside terms, 4*x=4x.
  4. Finally, the last terms, 4*-7, this equals -28.

Then, add all of the terms together x^{2} + -7x+4x+-28. To get the standard form, combine like terms, this comes out to x^{2} -3x-28.

3 0
3 years ago
-2x+15y=-24<br> 2x+9y=24 <br> solve the system of equation
zhuklara [117]

Answer:

x = 12, y = 0

Step-by-step explanation:

Use elimination.

24y = 0

y = 0

Then plug back into the second equation.

2x + 9(0) = 24

2x = 24

x = 12

Plug back into the first equation to check.

8 0
3 years ago
Polygon q is a scaled copy of polygon p using a scale factor of 1/2 polygon q’s area is what fraction of polygon p’s area?
san4es73 [151]

Answer:

Polygon q’s area is one fourth of polygon p’s area

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> polygon q’s area

y-----> polygon p’s area

so

z^{2} =\frac{x}{y}

In this problem we have

z=\frac{1}{2}

substitute

(\frac{1}{2})^{2} =\frac{x}{y}

(\frac{1}{4}) =\frac{x}{y}

x=\frac{1}{4}y

therefore

Polygon q’s area is one fourth of polygon p’s area

3 0
3 years ago
Read 2 more answers
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