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Natalija [7]
3 years ago
10

What is the area of a rectangle that has a base of 5 centimeters and a height of 2 centimeters

Mathematics
1 answer:
allsm [11]3 years ago
8 0

Answer:

10 cm^{2}

Step-by-step explanation:

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Nori had 2 2/12 bags of apples he used 1 5/12 bags of apples to make pies how many bags of apples does nori have left. 1. See an
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Answer:

Nori would have 9/12 of a bag left.

Step-by-step explanation:

she had 2 2/12 and she used 1 5/12 so you subtract them and get 9/12

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Select the fraction that is equal to 2/4<br> 1/5<br> 12/7<br> 1/2
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Answer:

1/2

hope this helps

have a good day :)

Step-by-step explanation:

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A medical company tested a new drug for possible side effects. The table
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The correct answer is b
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3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
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Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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Other standard-of-living measurements besides real GDP per capita may include _____.
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I'm pretty sure the answer is education
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