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kogti [31]
3 years ago
12

Help meee!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
kirill [66]3 years ago
4 0
So the awnser is 2-4i

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An airplane is at a location 800 miles due west of city X. Another airplane is at a distance of 1,200 miles southwest of city X.
andrezito [222]

Answer:

The distance between the two airplanes (to the nearest mile) is 1058 miles.

Step-by-step explanation:

An airplane A is at a location 800 miles due west of city X. So AX = 800 miles.

Another airplane is at a distance of 1,200 miles southwest of city X. So BX = 1200 miles.

The angle at city X created by the paths of the two planes moving away from city X measures 60°. So angle ∠AXB = 60°.

In triangle ΔAXB, AX = 800 miles, BX = 1200 miles, ∠AXB = 60°.

Using law of cosines:-

AB² = AX² + BX² - 2 * AX * BX * cos(∠AXB).

AB² = 800² + 1200² - 2 * 800 * 1200 * cos(60°).

AB² = 640000 + 1440000 - 2 * 960000 * 1/2

AB² = 2080000 - 960000

AB² = 1120000

AB = √(1120000) = 1058.300524

Hence, the distance between the two airplanes (to the nearest mile) is 1058 miles.

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The answer is:  " 9a² + 7a " .
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Note:    (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
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3 years ago
I just have one question left you don’t need to simplify if you give the answer
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It is either 400 or negative 400 because if you devide 12 by .03 it is 400
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X^2 -3x + 0 = 0 Factor and solve
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So if you subtract the 0 out from the left side, the equation is now x^{2}-3x=0. Since a x is common in both of the terms on the left side, you can factor it out, now making the equation look like x(x-3)=0. When factoring, each of the separate things (x and (x-3)), must equal zero while the other one doesn't matter. So in order for the equation to be 0, the only potential options for x is 0 and 3. Therefore x=0 and x=3 are the two solutions
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Can someone help me with this question
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Answer:

200 kids

Step-by-step explanation:

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