3 years ago

How do you solve x-3=6

1 answer:

5 0

x-3=6

Add + 3 to both sides

x=6+3

x=9

9-3=6

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DerKrebs [107]

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Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

So we have

$\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}$

Solving the quadratic equation, we have

$\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}$

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

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1 year ago