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fredd [130]
3 years ago
13

A cylinder has a base diameter of 16in and a height of 5in. What is its volume in cubic

Mathematics
2 answers:
Scrat [10]3 years ago
6 0

Answer:

  • 1004.8 in³

Step-by-step explanation:

d = 2r => r = d/2 = 16in/2 = 8 inches

V = Ab×h

= π·r²×h

= 3.14·(8in)²×5in

= 1004.8 in³

kompoz [17]3 years ago
3 0

Answer:

1005.31 cm^{3}

Step-by-step Explanation:

=>Given:

d = 16in (\frac{16}{2} = 8)

h = 5in

π = 3.14

Volume of cylinder = πr²h

=> Required:

Volume of Cylinder

Solution:

V = 3.14*8^{2}*5

V = 1005.31 cm^{3}

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Kobotan [32]

Answer:

1.ABC = 45°,DBE = 45°.  ABD = 135°,CBE = 135°

2.ABC = 62°, DBE = 62°, ABD =118°,CBE = 118°

Step-by-step explanation:

1.angle ABC = angle DBE because they are vertical.  You can write the equation 3x+38 = 5x+20 and find both angles.  When you solve, x=9.  You substitute it in.  ABD is equal to 180-45° because it is supplementary with ABC. ABD = CBE b/c vertical angles.

2.You do the same thing.  4x+2=5x-13,x=15.  You substitute in 15 for x and get 62°.  They are the equal angles.  For ABD you do 180 -62 since they are supplementary angles, which gets you 118 which applies for both because they are vertical angles.

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3 years ago
Manipulate the triangle so angle A measures 14° and angle B measures 62°. Which statement is true about angle C? The angle is ac
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Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
frosja888 [35]

Answer:

The polynomial will be f(x) = \frac{4}{9}x(x - 2)^{2}.

Step-by-step explanation:

The three degree polynomial function f(x) has zeros at x = 0 and at x = 4 having multiplicity 2.

Therefore, (x - 0) and (x - 4)² will be factors of the polynomial f(x).

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