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Vitek1552 [10]
3 years ago
14

the Ratio of Chaperones to student on a field trip is 2:7 . There are 14 Chaperones on the field trip . In all , how many chaper

ones and students are there?
Mathematics
2 answers:
ozzi3 years ago
5 0

Answer:

63

Step-by-step explanation:

If the 2 in the ratio translates to 14, 14/2=7. So the scale factor is 7. Now we multiply the 7*(Scale Factor)(7)= 49. In the end we add 14+49 to get 63.

Readme [11.4K]3 years ago
3 0

Answer: 63 people in total

Step-by-step explanation:

if the ratio is 2:7, then there are 2 chaperones per every 7 students. If there are 14 chaperones then 2 * 7 = 14, so you'd multiply 7 * 7 and get 49. Then add 49 and 14.

2:7

14:?

2/7 = 14/?

2 * 7 = 14

7 * 7 = 49

2/7 = 14/49

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what are the coordinates of that center of a circle if the endpoints of its diameter are a(8,-4) and b(-3,2)?
11111nata11111 [884]
You need to add 8 and -3 together to get 5 and divide 5 by 2 to get 2.5
That is the x coordinate
You then need to add 2 and -4 together to get -2 and divide by 2 to get -1
This is the y coordinate
(2.5,-1)
8 0
3 years ago
A circle has a diameter of 42 mm. What is the circumference of this circle? (use 22/7 for pi; show your work in numbers)
stellarik [79]

Answer:

132

Step-by-step explanation:

Find Radius (r)

42/2 = 21

Plug 21 into Circumference Equation

2πr (In this case, π is 22/7)

Simplify

42 (22/7)

<u>132</u>

8 0
3 years ago
A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The
disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ±  5.09

=-2.09, 8.09  is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0
3 years ago
How much is 50% of 10 liters of milk
juin [17]

Answer:

5 liters

Step-by-step explanation:

10 x 0.5 = 5

4 0
3 years ago
3. Find the value of a and b when<br>5+√6/5-√6 = a+b√6​
mr Goodwill [35]

The answer for A is,

a = 5 +  \frac{ \sqrt{6} }{ \sqrt{5} }  -  \sqrt{6}  -  \sqrt{6b}

And the answer for B is,

b = - 1 +  \frac{5 +  \frac{ \sqrt{6} }{ \sqrt{5} } - a  }{  \sqrt{6} }

hope it helps.

sorry of its wrong.

4 0
3 years ago
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