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IgorC [24]
3 years ago
10

Find the area and perimeter of the following triangle with the given vertices:

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0
Find the area and perimeter of the following triangle with the given vertices:
(1, 2), (8, 2) and (3, 6)
Explain your reasoning; show all your work for full credit!

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Are all sides of the right angle have sides that are parallel
nydimaria [60]

-- The two sides of a right <u>angle</u> intersect and make the angle.
So do the sides of any other angle. So they can't be parallel.

-- No two sides of a right <u>triangle</u> ... or any other triangle ...can be parallel.


8 0
3 years ago
What is the solution to the equation log2 (5x - 2) = 3?
Advocard [28]

From log BNE to BEN

X=2

if you want explaination then ask me

4 0
3 years ago
Can someone help and explain how to find domain and range I'm confused doing it on the last to I know how to do it with x just n
Thepotemich [5.8K]

Answer:

Domain is the set of inputs that will give you a defined output.

In example, f(x)=5/x, the domain would be all real numbers except for 0, because if it would be 0, it would be 5/0 which would be undefined.

Range is the set of outputs that are possible.

In example, f(g)=g(0), the range would be 0.

8 0
2 years ago
PLEASE HELP ASAP! NO SCAMS ALLOWED!
Kitty [74]

Answer:

Step-by-step explanation:

I used calculus for this, as I'm not sure there's any other way to do it and to do it as easily. This is the volume of a solid found by using the disk method of rotation:

V=\pi\int\limits^a_b {[R(x)]^2-[r(x)]^2} \, dx

where R(x) is the outer shell of the solid and r(x) is the space inbetween the solid and the axis of rotation. There is no space between the solid and the axis of rotation, so r(x) = 0. R(x) is the height of the solid which is 3. Therefore, f(x) = 3 and that's the function we put into the formula with the lower bound of 3 and the upper bound of 5:

V=\pi\int\limits^5_3 {3^2}-0^2 \, dx  and

V-\pi\int\limits^5_3 {9} \, dx  and integrating:

V=\pi(9x\left \} {{5} \atop 3}} \right. and using the First Fundamental Theorem of Calculus:

V = π(9(5) - 9(3)) and

V = π(45 - 27) so

V = 18π units cubed or in decimal format,

V = 56.549 units cubed

6 0
2 years ago
If the class mark and class size of the class
Gemiola [76]

Answer:

The class interval is: 20-30

Step-by-step explanation:

Let l be the lower class limit and u be the upper class limit.

Then according to given statement that class mark is 25

\frac{l+u}{2} = 25\\l+u = 50\ \ \ Eqn\ 1

And

Class size is 10

So, the second equation will be:

u-l = 10\ \ \ \ Eqn\ 2

Adding equation 1 and 2

l+u+u-l = 50+10\\2u = 60\\\frac{2u}{2} = \frac{60}{2}\\u = 30

Now putting u =30 in equation 1

l+u = 50\\l+30 = 50\\l = 50-30\\l = 20

A class interval is written in the form that lower limit comes first and upper limit comes second.

So,

20-30

Hence,

The class interval is: 20-30

7 0
3 years ago
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