Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
I hope this helps you
l=x+2
w=2x-5
(x+2)(2x-5)=56
2x^2-x-10=56
2x^2-x-66=0
2x +11
x -6
(2x+11)(x-6)=0
x=6
Part 1:
180 = 5p+98 + 9p-2
180 = 14p + 96
84 = 14p
6 = p
part 2:
angle S will be the same as angle Q, so:
9p-2
9(6)-2
54-2
M
No entiendo....................
Answer:
Y = 60 degrees and X = 12
Step-by-step explanation:
x+3 and 15 are congruent so x+3 = 15, 12+3 = 15 therefore x = 12
y = 60 vertically opposite angles are equal. :D