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3 years ago

A trapezoid has an area of 35 square inches. It has a base of 8 inches and 6

Mathematics

1 answer:

Liula [17]3 years ago

5 0

the height of the trapezoid of 5, i think.

my work:

i used this formula: 2 x a + b / A

so, you plug in what you know.

2 x 8+6 / 35 = 5

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Help will mark Brainliest

yarga [219]

Answer:

C. is the correct answer

Step-by-step explanation:

A. is incorrect because the sequence does not start with 15

B. is incorrect because the pattern increases by 5, not multiplied by 5

C. is correct because all of the even numbers in the pattern do end in 0

D. is incorrect because even numbers don't end in 5's

Hope this helps!

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2 years ago

Read 2 more answers

A box plot is also known as a(n) box-and-whisker plot. Use the box plot below to find each of the following.

VLD [36.1K]

Answer:

the min is 53 the max is 90 median is 65 first quartile is 60 and the third quartile is 82

Step-by-step explanation:

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3 years ago

How do you solve for y in the equation: <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%3Dy-6" id="TexFormula1" title

kozerog [31]

No it isn't.

Explanation:

x/y * y = (y-6) * y

x = y^2 - 6y

A function gives just one y for every x

In this case there will always be 2 y's for every x

Example:

y can be

y = 6

y =−6

(0,-6) & (0,6)

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3 years ago

Last month, a factory produced 800 television sets. This month, the same factory produced 1,064 television sets. The increase in

Harlamova29_29 [7]

Your answer is 264
1,064 - 800= 264

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3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

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3 years ago