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atroni [7]
3 years ago
14

Use the distributive property to fill in the blanks below.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

(5×7)-(5×6) = 5×(7-6)

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PLEASE HELP ME what is the solution to the system of equations?
masha68 [24]
Times the bottom equation by -4 to cancel out the x’s.
Add the equations.
Solve for y.
Plug in y to find x.

8 0
3 years ago
In Crestview Middle School, 12 out of 16 students are right handed. If there are 400 students in the school, how many are right
DerKrebs [107]

Answer:

the answer is 300

Step-by-step explanation

there are 16 people so we divide that by the total number of students

400 divided by 16 = 25

since there are 12 right handed in each group we multpily it by 12

25 x 12 = 300

and theres your answer!

7 0
3 years ago
Idk why I can’t get this ?! number two plz
Arturiano [62]
The only possible outcome to this would be any number greater or less than 361 in the 300’s
7 0
3 years ago
Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans
Vaselesa [24]

Answer: 1\dfrac{11}{12}\text{ pounds}

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= 1\dfrac{1}{4} pounds

=\dfrac{5}{4} pounds.

Amount lemon jelly beans = 2\dfrac{1}{3}pounds

=\dfrac{7}{2} pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

=(\dfrac{5}{4}+\dfrac{7}{3}) pounds

=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}

Amount of jelly beans she gave away = 1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

=\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}

She has left 1\dfrac{11}{12}\text{ pounds} of jelly beans.

6 0
3 years ago
Sara and liz if your reading this send a screenshot NOW
hjlf

yeldyldtrlkrdyyrydkrysykryserorokyseiedtoosoroyr

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3 years ago
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